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(D) The de-Broglie wavelength $\lambda$ is related to the momentum $p$ of a particle by the equation $\lambda = \frac{h}{p}$, where $h$ is Planck's co

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(D) The de-Broglie wavelength $\lambda$ is related to the momentum $p$ of a particle by the equation $\lambda = \frac{h}{p}$, where $h$ is Planck's constant.This equation can be rewritten as $p \lambda = h$.Since $h$ is a constant, the product of $p$ and $\lambda$ is constant $(p \lambda = 	ext{constant})$.This relationship represents a rectangular hyperbola in the $p-\lambda$ plane, where $p$ decreases as $\lambda$ increases.Therefore, the graph shown in Figure $D$ correctly represents this inverse relationship.

Which of the following figures represents the variation of particle momentum $p$ and the associated de-Broglie wavelength $\lambda$?

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